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  4. Iterables and Iterators
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Iterables and Iterators

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933 Discussions

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  • shaswathkumar
     + 0 comments
    from itertools import combinations

length = int(input())
s = input().split()
k = int(input())
count = 0
for tup in combinations(s,k):
    if any(elem == 'a' for elem in tup):
        count += 1

print(count / len(list(combinations(s,k))))

  • codeandbeyondco
     + 0 comments

    This problem directing the old version documentation of itertools. It should be updated with the new version. https://docs.python.org/3.8/library/itertools.html

  • arushigupta1080
     + 0 comments

    i saw every answer but no where its mentioned that we need to iterate the list part or n times input

  • maluisamrok
     + 0 comments

    this work so good and fast!!!

    import itertools
N =int(input())
cadena =input().split()
k=int(input())

print(len(list(itertools.filterfalse(lambda a: 'a' not in a,itertools.combinations(cadena, k))))/(len (list(itertools.combinations(cadena, k)))))

  • neha_singh19aug
     + 0 comments
    from itertools import combinations

if __name__ == '__main__':
    length,l1,K = int(input()),input().split(),int(input())
    list_combos = list(combinations(l1, K))
    counter1 = 0
    for comb in list_combos:
            if 'a' in comb:
                counter1 += 1
    print(counter1 / len(list_combos))