python3

def isFibo(n):
    fibo = []
    a = 0
    b = 1
    fibo.append(a)
    for i in range(1, 101):
        fibo.append(b)
        c = a+b
        a = b
        b = c
    
    if n in fibo:
        return "IsFibo"
    else:
        return "IsNotFibo"