import java.io.*;
import java.util.*;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class Solution {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int t = scanner.nextInt(); scanner.nextLine();
        String u = "(25[0-5]|2[0-4]\\d|1?\\d?\\d)"; //0 to 255
        String regex_ipv4 = String.format("^(%s\\.){3}%s$",u,u); //u.u.u.u
        String v = "[a-fA-F0-9]{1,4}"; //4 hexadecimal digits
        String regex_ipv6 = String.format("^(%s\\:){7}%s$",v,v); //v:v:v:v:v:v:v:v (8 groups)
        Pattern pattern_ipv4 = Pattern.compile(regex_ipv4);
        Pattern pattern_ipv6 = Pattern.compile(regex_ipv6);
        for(int i=0;i<t;i++)
        {   String str = scanner.nextLine();
            Matcher matcher_ipv4 = pattern_ipv4.matcher(str);
            Matcher matcher_ipv6 = pattern_ipv6.matcher(str);
            if (matcher_ipv4.find())    System.out.println("IPv4");
            else if (matcher_ipv6.find())   System.out.println("IPv6");
            else    System.out.println("Neither");
        }
    }
}

/*
---------- v = "[a-fA-F0-9]{1,4}" ---------------
4 hexadecimal digits.
Hexadecimal means either using a-f or 0-9
ff translates to 00ff. So no of digits can be either 1,2,3 or 4. So use {1,4}

---------- u = "(25[0-5]|2[0-4]\\d|1?\\d?\\d)" ---------------
Means 0 to 255
3 digit combinations: 
    25[0-5]  or 2[0-4][0-9] or 1[0-9][0-9] 
2 digit combinations:
    [0-9][0-9]
1 digit combinations:
    [0-9]
Combining 1 digit and 2 digit combinations: becomes: [0-9]?[0-9]
    Combine this with 1[0-9][0-9] : becomes : 1?[0-9]?[0-9]
So final set of combinations : becomes:
    25[0-5]  or 2[0-4][0-9] or 1?[0-9]?[0-9]


*/