Discussion on Detect Floating Point Number Challenge

Sort by

recency

|

545 Discussions

|

5 days ago+ 0 comments

import re
T= int(input())
for i in range(T):
    if re.match(r'(^(\d|\+|\-)\d*\.\d*)$|(^\.\d*$)',input()):
        print("True")
    else:
        print("False")

3 months ago+ 1 comment

import re t=int(input()) pattern=r'^[+-]?\d*.\d+$' for _ in range(t): s=input() if re.match(pattern,s): print(True) else: print(False)

2 months ago+ 0 comments

Adding try except passed all the test cases. It is needed for the constraint: "Number must not give any exceptions when converted using float(N)"

import re T = int(input()) pattern = r'^[+-]?\d*.\d+$'

for _ in range(T): N = input() try: num = float(N) match = re.search(pattern,N) print(bool(match)) except: print(False)

3 months ago+ 0 comments

import re t = int(input()) for i in range(t): n = input() print(bool(re.match(r'^[+-]?\d*.\d+$', n)))

3 months ago+ 0 comments

import re T = int(input().strip())

float_number_pattern = r"^[+-]?([0-9][.][0-9]+|[0-9]+[.][0-9])$"

for _ in range(0,T): string = input().strip() if re.match(float_number_pattern,string): print("True") else: print("False")

3 months ago+ 0 comments

import re
pattern = r"^[+-]?\d*\.\d+$"
T = int(input())

for testcase in range(T):
    N = input()
    if re.match(pattern,N): 
        print(True) 
    else: 
        print(False)

Sort by

|

545 Discussions

|

Cookie support is required to access HackerRank

Please signup or login in order to view this challenge