Insertion Sort is a simple sorting technique which was covered in previous challenges. Sometimes, arrays may be too large for us to wait around for insertion sort to finish. Is there some other way we can calculate the number of shifts an insertion sort performs when sorting an array?
If is the number of elements over which the element of the array has to shift, then the total number of shifts will be ... + .
Example
Array Shifts
[4,3,2,1]
[3,4,2,1] 1
[2,3,4,1] 2
[1,2,3,4] 3
Total shifts = 1 + 2 + 3 = 6
Function description
Complete the insertionSort function in the editor below.
insertionSort has the following parameter(s):
- int arr[n]: an array of integers
Returns
- int: the number of shifts required to sort the array
Input Format
The first line contains a single integer , the number of queries to perform.
The following pairs of lines are as follows:
- The first line contains an integer , the length of .
- The second line contains space-separated integers .
Constraints
Sample Input
2
5
1 1 1 2 2
5
2 1 3 1 2
Sample Output
0
4
Explanation
The first query is already sorted, so there is no need to shift any elements. In the second case, it will proceed in the following way.
Array: 2 1 3 1 2 -> 1 2 3 1 2 -> 1 1 2 3 2 -> 1 1 2 2 3
Moves: - 1 - 2 - 1 = 4