is not working. Also tried the following import re

pattern = r".*+"

try: re.compile(pattern)

except re.error: print("Non valid regex pattern") exit() Please suggest what is the correct solution, else is there some thing with the validator in hackerrank ?

Please except re.error: print("Non valid regex pattern") exit()

`In Python 2

import re

num_test_cases = int(raw_input())

for _ in range(num_test_cases): regex = raw_input() try: re.compile(regex) print(True) except re.error: print(False)

`

This works with PyPy3. Thank you codersaad for the idea. This is the same code but without a function.

import re

n = int(input())

for _ in range(n): regex = input().strip() try: if re.search(r'(*|+|\?){2,}', regex): print("False") else: re.compile(regex) print("True") except re.error: print("False")

This works with PyPy3. Thank you codersaad for the idea. This is the same code but without a function.

import re

n = int(input())

for _ in range(n): regex = input().strip() try: if re.search(r'(*|+|\?){2,}', regex): print("False") else: re.compile(regex) print("True") except re.error: print("False")

my solution: import re for i in range(int(input())): try: re.compile(input()) print(True) except re.error: print(False) but it is giving output as TRUE TRUE and hence failing the sample test case. Although i did solve it using python 2 can anyone help me with a pypy3 solution