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  1. Prepare
  2. Mathematics
  3. Number Theory
  4. Identify Smith Numbers
  5. Discussions

Identify Smith Numbers

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  • greenbethany
     + 0 comments

    Great post on Smith Numbers! For those diving deeper into number theory, it's fascinating to see how these numbers bridge the gap between math and patterns. Have you considered how tools like Drift Boss can help visualize complex concepts like these? Utilizing games or puzzles could enhance understanding by making the learning process more interactive. Keep sharing such insightful content!

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     + 0 comments

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  • 2k23_csai2310233
     + 0 comments
    public static int solve(int nn) {
    // Write your code here
                  int ds=0;
        int temp=nn;
        int n=nn;
        List<Integer> a=new ArrayList<>();
        while(temp>0){
            ds+=temp%10;
            temp/=10;
        }
        
         while (n % 2 == 0) {
           a.add(2);
            n /= 2;
        }
        for (int i = 3; i <= Math.sqrt(n); i += 2) {
            while (n % i == 0) {
                a.add(i);
                n /= i;
            }
        }
 
        if (n > 2)
           a.add(n);
        
        
        int fsum=0;
        
        for(int i:a)
        {
            while(i>0){
                fsum+=i%10;
                i=i/10;
            }
        }
        //System.out.println(a);
        if(fsum==ds)
            return 1;
        return 0;
    }

  • 2k23_cscys231212
     + 0 comments
    #include <vector>
#include <cmath>
using namespace std;

// Function to calculate the sum of digits of a number
int sumOfDigits(int n) {
    int sum = 0;
    while (n > 0) {
        sum += n % 10;
        n /= 10;
    }
    return sum;
}

// Function to find the prime factors of a number
vector<int> primeFactors(int n) {
    vector<int> factors;
    for (int i = 2; i <= sqrt(n); ++i) {
        while (n % i == 0) {
            factors.push_back(i);
            n /= i;
        }
    }
    if (n > 1) {
        factors.push_back(n);
    }
    return factors;
}

// Function to check if a number is a Smith number
bool isSmithNumber(int n) {
    if (n < 2) return false; // Numbers less than 2 are not Smith numbers

    vector<int> factors = primeFactors(n);

    if (factors.size() == 1) {
        return false; // Prime numbers are not Smith numbers
    }

    int digitSum = sumOfDigits(n);
    int factorsDigitSum = 0;

    for (int factor : factors) {
        factorsDigitSum += sumOfDigits(factor);
    }

    return digitSum == factorsDigitSum;
}

int main() {
    int n;
    cin >> n;

    if (isSmithNumber(n)) {
        cout << 1 << endl;
    } else {
        cout << 0 << endl;
    }

    return 0;
}