n=int(input())
k=[]
l=[]
f=0
z=[]
for i in range(n):
    a,b=input().split()
    for j in range(1,2*int(a)):
        if j<int(a):
            k.append(j)
        elif j==int(a):
            k.append(j)
            k.append(-j)
        elif j>int(a):
            x=j-2*int(a)
            k.append(x)
    if int(b)>0:
        l.append(int(b))
        f=k[int(b)+int(b)-1]
        while f in k and l.count(f)<=1:
            if f>0:
                if f not in l:
                    l.append(f)
                f=k[f+f-1]
            elif f<0:
                if f not in l:
                    l.append(f)
                f=k[k[f]+f]
                l.append(f)
    l=list(dict.fromkeys(l))
    if int(b)<0:
        l.append(int(b))
        f=k[k[int(b)]+int(b)]
        while f in k and l.count(f)<=1:
            if f>0:
                if f not in l:
                    l.append(f)
                f=k[f+f-1]
            elif f<0:
                if f not in l:
                    l.append(f)
                f=k[k[f]+f]
                l.append(f)
    l=list(dict.fromkeys(l))
    k.sort()
    l.sort()
    for s in k:
            if s not in l:
                z.append(s)
    u=0
    for i in z:
        u+=1
    print(u)
		
		My test cases 0 and 1 ran successfully, but for the remaining test cases, it says terminated due to timeout. Please suggest edits to my code.
    k=[]
    l=[]
    f=0
    z=[]