I remember struggling with a similar grid puzzle a while back. At first, it seemed impossible to cover all the cells, especially with those blackened spots messing up potential placements. But after some trial and error, I figured out how to fit the tiles just right—kind of like when I was trying to buy tretinoin cream online and had to navigate all the different options to find the right one. Some grids just work out, and others? Well, they’re doomed from the start!

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~10 lines Python, 100%, cool bit things

If you figure out what the numbers mean I'll buy you a virtual coffee :D

@cache
def f(a,b):
    x=((a&3)<<2)|(b&3)
    if a==b:
        return True
    if (a,b)==(0,1) or (a,b)==(1,0) or x in {6,11,14}:
        return False
    if x in {2,7,8,13}:
        return f(a>>1,b>>1)
    if x in {0,3,5,9,10,12,15}:
        return f(a>>2,b>>2)
    return f(a>>1,(b>>1)|1) or f((a>>1)|1,b>>1)

def hexagonalGrid(a, b):
    return "YES" if f(int(a,2),int(b,2)) else "NO"

Here is Hexagonal Grid problem solution - https://programs.programmingoneonone.com/2021/07/hackerrank-hexagonal-grid-problem-solution.html

My python3 example with O(n) complexity:

def hexagonalGrid(a, b):
    if ((a.count('1') + b.count('1')) % 2 != 0):
        return 'NO'
    white = 0
    block = False
    for i in range(len(a)):
        if (a[i] == '1'):
            if block and white % 2 != 0:
                return 'NO'
            block = True
        elif (a[i] == '0'):
            block = False
            white += 1
        if (b[i] == '1'):
            if block and white % 2 != 0:
                return 'NO'
            block = True
        elif (b[i] == '0'):
            block = False
            white += 1          
    return 'YES'