Discussion on Hex Color Code Challenge

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393 Discussions

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3 weeks ago+ 0 comments

import re
import string
jinx = []
powder = []
p = r'#[0-9a-fA-F]{3}(?:[0-9a-fA-F]{3})?\b'
for _ in range(int(input())):
inpt = input()
if ';' in inpt:
isha = re.findall(p,inpt)
jinx.append(isha)
for pow in jinx:
for color in pow:
powder.append(color)
print('\n'.join(powder))

4 weeks ago+ 0 comments

` Import re

for _ in range(int(input())): for hex_code in re.findall(r"(?<=.)#[\dA-Fa-f]{3,6}", input()): print(hex_code) `

2 months ago+ 0 comments

import re 

N = int(input())

hex_code = r'#[0-9A-Fa-f]{3,6}(?=[^\w-])'

css_colors = []

for _ in range(N):
    line = input()
    css_colors.extend(re.findall(hex_code, line))
    
print('\n'.join(css_colors))

3 months ago+ 0 comments

import sys, re

text = sys.stdin.read().splitlines()[1:]
HEX_pattern = r"[#][0-9a-f]{3,6}"

index_list = []
line_list = []
match = ''

i = 0 
for line in text:
    if not re.search(r"^(#|{|})", line): 
            index_list.append(i)
    i+=1

for index in index_list:
    line_list.append(text[index])

match ='\n'.join(re.findall(HEX_pattern, ''.join(line_list), flags=re.I))
print(match)

4 months ago+ 0 comments

import re
pattern = r'#[0-9A-Fa-f]{6}\b|#[0-9A-Fa-f]{3}\b'
n = int(input().strip())
inside = False
for _ in range(n):
    t = input()
    if "{" in t: 
        inside = True
    elif "}" in t: 
        inside = False
    elif inside:
        [print(x) for x  in re.findall(pattern,  t)]

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