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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Happy Ladybugs
  5. Discussions

Happy Ladybugs

  • alex_k5
     + 0 comments

    from collections import Counter

    def happyLadybugs(b):

    count_b = Counter(b)
mc = count_b.most_common()
if len(mc)!=1 and ((mc[-1][1]== 1 and mc[-1][0]!= '_') or mc[-2][1]== 1):
    return 'NO'
else:
    if '_' in b:
        return 'YES'
    for i in mc:
        if count_b[i[0]]==1 or b.rfind(i[0])-b.find(i[0])+1 != count_b[i[0]]:
            return 'NO'
        if i == mc[-1]:
            return 'YES'