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  1. Prepare
  2. Algorithms
  3. Strings
  4. HackerRank in a String!
  5. Discussions

HackerRank in a String!

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1079 Discussions

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  • alban_tyrex
     + 0 comments

    My easy c++ solution, here is the explanation : https://youtu.be/N3lhtXtqIoU

    string hackerrankInString(string s) {
    string target ="hackerrank";
    int currentIndex = 0;    
    for(int i = 0; i < s.size(); i++){
        if(s[i] == target[currentIndex]){
            currentIndex++;
            if(currentIndex == target.size()) return "YES";
        }
    }
    return "NO";
}

  • benjamin_s1_e
     + 0 comments

    Went this way around with Javascript:

    const HRS = "hackerrank";
function hackerrankInString(s: string): string {
    let matching = 0;
    for (let i = 0; i < s.length && matching < HRS.length; i++) {
        if (s[i] === HRS[matching]) matching++;
    }
    return matching === HRS.length ? "YES" : "NO";
}

  • 0xmillennium
     + 0 comments

    Try the sript below on python and thnak me later:)

    def hackerrankInString(s):
    return "YES" if re.search(r'h.*a.*c.*k.*e.*r.*r.*a.*n.*k.*', s) else "NO"

  • tanuchauhan
     + 1 comment

    def hackerrankInString(s): # Write your code here

    fs = 'hackerrank'
if len(s) < len(fs):
        return 'NO'
for i in range(len(fs)):
        for c in s:
                if c == fs[i]:
                        i +=1
                if i == len(fs):
                        return 'YES'
        return 'NO'

  • jmcparland
     + 0 comments

    Haskell

    module Main where

import Control.Monad (replicateM_)

solve :: String -> String
solve = go "hackerrank"
  where
    go [] _ = "YES"
    go _ [] = "NO"
    go (x : xs) (y : ys)
      | x == y = go xs ys
      | otherwise = go (x : xs) ys

main :: IO ()
main = do
  n <- readLn :: IO Int
  replicateM_ n $ getLine >>= putStrLn . solve