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  1. Prepare
  2. Algorithms
  3. Strings
  4. Funny String
  5. Discussions

Funny String

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1336 Discussions

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  • illogicalsleepi1
     + 0 comments
    def diff(arr):
    res=[]
    for i in range(len(arr)-1):
        res.append(abs(ord(arr[i])-ord(arr[i+1])))
    return res

def funnyString(s):
    st=list(s)
    rev=st[::-1]
    res1=diff(st)
    res2=diff(rev)
    return 'Funny' if res1==res2 else 'Not Funny'

    or

    def funnyString(s):
    for i in range(1, len(s)//2+1):
        if abs(ord(s[i])-ord(s[i-1])) != abs(ord(s[-i])-ord(s[-i-1])):
            return 'Not Funny'
    return 'Funny'

  • alban_tyrex
     + 0 comments

    Here is my simple c++ solution, video explanation here : https://youtu.be/gcNAo9voHvk.

    string funnyString(string s) {
    string r = s;
    reverse(r.begin(), r.end());
    for(int i = 1; i < s.size(); i++){
        if(abs(s[i]-s[i-1]) != abs(r[i]- r[i-1])) return "Not Funny";
    }
    return "Funny";
}

  • alex_k5
     + 0 comments
    def funnyString(s):
    for i in range(1, math.ceil(len(s)/2)+1):
        if abs(ord(s[i])-ord(s[i-1])) != abs(ord(s[-i])-ord(s[-i-1])):
            return 'Not Funny'
    return 'Funny'

  • hpareek1995
     + 1 comment

    My Python code

    def funnyString(s): s2 = s[::-1]

    lst1 = [abs(ord(s[i]) - ord(s[i-1])) for i in range(1, len(s))]
lst2 = [abs(ord(s2[i]) - ord(s2[i-1])) for i in range(1, len(s2))]

if lst1 == lst2:
    return 'Funny'
else:
    return 'Not Funny'

  • zenasmukadom
     + 0 comments
    public static String funnyString(String s) {
    
        StringBuilder build = new StringBuilder(s);
        String revStr = build.reverse().toString();
        
        int n = s.length();
        char[] firstStr = s.toCharArray();
        char[] secondStr = revStr.toCharArray();
        
        for(int i=0; i<n-1; i++){
            
            int diff1 = Math.abs((int)firstStr[i] - (int)firstStr[i+1]);
            int diff2 = Math.abs((int)secondStr[i] - (int)secondStr[i+1]);
            
            if(diff1 != diff2){
                return "Not Funny";
            }
            
        }
        return "Funny";

    }