You are viewing a single comment's thread. Return to all comments →
MySQL code
select h.hacker_id, h.name from submissions s inner join challenges c on s.challenge_id = c.challenge_id inner join difficulty d on c.difficulty_level = d.difficulty_level inner join hackers h on s.hacker_id = h.hacker_id where s.score = d.score and c.difficulty_level = d.difficulty_level group by h.hacker_id, h.name having count(s.hacker_id) > 1 order by count(s.hacker_id) desc, s.hacker_id asc
Seems like cookies are disabled on this browser, please enable them to open this website
Top Competitors
You are viewing a single comment's thread. Return to all comments →
MySQL code