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SELECT S.hacker_id, H.name
FROM submissions S
JOIN challenges C ON S.challenge_id = C.challenge_id
JOIN difficulty D ON C.difficulty_level = D.difficulty_level
JOIN hackers H ON S.hacker_id = H.hacker_id
WHERE S.score = D.score
GROUP BY S.hacker_id, H.name
HAVING COUNT(S.submission_id) > 1
ORDER BY COUNT(S.submission_id) DESC, hacker_id;
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SELECT S.hacker_id, H.name FROM submissions S JOIN challenges C ON S.challenge_id = C.challenge_id JOIN difficulty D ON C.difficulty_level = D.difficulty_level JOIN hackers H ON S.hacker_id = H.hacker_id WHERE S.score = D.score GROUP BY S.hacker_id, H.name HAVING COUNT(S.submission_id) > 1 ORDER BY COUNT(S.submission_id) DESC, hacker_id;