SELECT 
     H.Hacker_id,H.name
FROM 
    Hackers H 
JOIN 
    Submissions S ON H.Hacker_id = S.Hacker_id 
JOIN 
    Challenges C ON S.challenge_id = C.challenge_id 
JOIN
    Difficulty D ON C.difficulty_level = D.difficulty_level 
WHERE 
    S.score = D.score
GROUP BY 
    H.hacker_id, H.name
HAVING  
    COUNT(DISTINCT S.challenge_id) > 1
ORDER BY 
    COUNT (DISTINCT S.challenge_id) DESC,
    H.hacker_id ASC;