SELECT cte.hacker_id, cte.name
FROM (
SELECT h.hacker_id, h.name, COUNT(s.challenge_id) AS total_ch
FROM Hackers h
JOIN Submissions s ON h.hacker_id = s.hacker_id
LEFT JOIN Challenges c ON s.challenge_id = c.challenge_id
JOIN Difficulty d ON c.difficulty_level = d.difficulty_level AND s.score = d.score
GROUP BY h.hacker_id, h.name
ORDER BY total_ch DESC, h.hacker_id ASC) AS cte
WHERE cte.total_ch > 1