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select s.hacker_id,h.name
from submissions as s join
challenges as c on
s.challenge_id = c.challenge_id
join difficulty as d on
c.difficulty_level = d.difficulty_level
join hackers as h on
s.hacker_id = h.hacker_id
where d.score = s.score
group by s.hacker_id,h.name
having count()>1
order by count() desc,s.hacker_id;
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select s.hacker_id,h.name from submissions as s join challenges as c on s.challenge_id = c.challenge_id join difficulty as d on c.difficulty_level = d.difficulty_level
join hackers as h on s.hacker_id = h.hacker_id where d.score = s.score group by s.hacker_id,h.name having count()>1 order by count() desc,s.hacker_id;