SELECT h.hacker_id, h.name
FROM submissions s
JOIN challenges c ON s.challenge_id = c.challenge_id
JOIN difficulty d ON c.difficulty_level = d.difficulty_level 
JOIN hackers h ON s.hacker_id = h.hacker_id
WHERE s.score = d.score 
GROUP BY h.hacker_id, h.name
HAVING COUNT(s.hacker_id) > 1
ORDER BY COUNT(s.hacker_id) DESC, s.hacker_id ASC