#include <stdio.h>
#include <string.h>

int main() {
    char str[1000];
    int count=0;
    char num_arr[10]={'0','1','2','3','4','5','6','7','8','9'};
    scanf("%s",str);
    for(int i=0;i<10;i++){ 
        count=0;    //assigning count=0 for each digit 0-9
        for(int j=0;j<strlen(str);j++){
            if(str[j]==num_arr[i]){ //find occurences of each digit in given string 
                count++;
            }
        }
        printf("%d ",count);
    }
    
    return 0;
}

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
    /* Enter your code here. Read input from STDIN. Print output to STDOUT */    
    char *a = (char*)malloc(1000 * (sizeof(char)));
    fgets(a, 1000, stdin);
    int hmm[10] = {0};
    for(int i=0; i < strlen(a); i++ ){
        if (a[i] >= '0' && a[i] <= '9'){  //difference in ascii character address turns str into int
            hmm[a[i] - '0']++;
        }
    }
    for (int i = 0; i < 10; i++) {
        printf("%d ", hmm[i]);
    }
    free(a);
    return 0;
}

#include <stdio.h>
#include <string.h>

int main() {
    char s[1000];
    scanf("%s", s);

    int digit_counts[10] = {0}; // Initialize counts for each digit to 0

    // Iterate over each character in the string
    for (int i = 0; i < strlen(s); i++) {
        // Check if the character is a digit
        if (s[i] >= '0' && s[i] <= '9') {
            // Increment the count for the corresponding digit
            digit_counts[s[i] - '0']++;
        }
    }

    // Print the counts for each digit
    for (int i = 0; i < 10; i++) {
        printf("%d ", digit_counts[i]);
    }
    printf("\n");

    return 0;
}

#include <stdio.h>
#include <stdlib.h>

int main() {
    char *s = (char*)malloc(1000*sizeof(char));
    int i=0,arr[10] = {0};
    
    scanf("%[^\n]",s);
    
    while(s[i] != '\0'){
        if((s[i] - '0')<=9) 
            arr[(s[i]- '0')]++;
        ++i;
    }
    
    for(i=0;i<=9;i++){
        printf("%d ", arr[i]);
    }
        
    return 0;
}