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long flippingBits(long n) { return 4294967295-n; }

Here is my c++ solution, you can watch the video explanation here : https://youtu.be/eZ0lTIzOjhQ

V1

long flippingBits(long n) {
    long result = 0;
    for(int i = 31; i >= 0; i--) {
        if(n >= pow(2, i)){
            n -= pow(2,i);
        }
        else result += pow(2, i);
    }
    return result;
}

V2

long flippingBits(long n) {
    return 4294967295 ^ n;
}

def flippingBits(n): num = ~n return 4294967296 + num