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  1. Prepare
  2. Python
  3. Strings
  4. Find a string
  5. Discussions

Find a string

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3394 Discussions

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  • Diversificado
     + 0 comments

    This is a simple solution.

    def count_substring(string, substring):

times = 0

for pos, char in enumerate(string):

    if(char == sub_string[0] and string[pos:pos + len(sub_string)] == sub_string):
        times += 1         

return times

  • doyouDance
     + 0 comments
    import re

def count_substring(string, sub_string):
    iters = re.findall(rf'(?=({re.escape(sub_string)}))', string)
    return len(iters)

  • jdev42283
     + 0 comments

    def count_substring(string, sub_string): tot = 0 i = string.find(sub_string) if(i >= 0): tot += 1 if(i == -1): return tot else: while(i != -1): i = string.find(sub_string, i+1) if(i == -1): break else: tot += 1 return tot

    Mam check this logic once please..

  • nicko_strife
     + 0 comments

    Happy with my code as it is easy to ready and digest

    def count_substring(string, sub_string):
    x = len(string)
    y = len(sub_string)
    count = 0
    for i in range(0, x):
        if sub_string == string[ i : i+y ]:
            count += 1
    return count

  • provungshu
     + 0 comments

    easier version

    def count_substring(string, sub_string): counter = 0 while sub_string in string: counter += 1 find = string.find(sub_string) string = string[find + 1:] return counter