We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Python
  3. Strings
  4. Find a string
  5. Discussions

Find a string

Sort by

recency

|

3408 Discussions

|

  • surajbhand2003
     + 0 comments

    simple approach

    def count_substring(s, sub): count = 0 

    #   indiaisiajsndiasd   ia
k = 0
for i in range(0, len(s)):
    p = s.find(sub, k, len(s))
    if i == p:
        count = count + 1
        if p + len(sub) < len(s):
            k = p + 1

return count

  • s_fadel
     + 0 comments
    def count_substring(string, sub_string):
    count = 0
    for element in range(0, len(string) + 1):
        if string[element:len(sub_string) + element] == sub_string:
            count += 1  
    return count

  • fluenoriph
     + 0 comments

    def count_substring(string, sub_string): i = c = 0 j = len(string)

    for _ in range(j):
    p = string.find(sub_string, i, j)
    if p != -1:
        c += 1
        i = p + 1

return c

  • virenbodar1
     + 0 comments
      def count_substring(string, sub_string):
        count=0
for i in range(len(string)):
        if string[i : i+len(sub_string)]==sub_string:
            count+=1
    return count

  • GaryRamu
     + 0 comments

    SOLUTION:

    def count_substring(string, sub_string): count = 0 for i in range(len(string) - len(sub_string) + 1): if string[i:i + len(sub_string)] == sub_string: count += 1 return count

    if name == 'main': string = input().strip() sub_string = input().strip()

    count = count_substring(string, sub_string)
print(count)