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My Java 8 Solution

public static void extraLongFactorials(int n) {
        BigInteger result = BigInteger.ONE;
        
        for (int i = 1; i <= n; i++) {
            result = result.multiply(BigInteger.valueOf(i));
        }
        
        System.out.println(result);
    }

Here is problem solution in Python, Java, C++, C and Javascript - https://programmingoneonone.com/hackerrank-extra-long-factorials-problem-solution.html

void multiply(int x, vector& result, int& result_size) { int carry = 0;

for (int i = 0; i < result_size; i++) {
    int prod = result[i] * x + carry;
    result[i] = prod % 10;   
    carry = prod / 10;   
}


while (carry) {
    result[result_size] = carry % 10;
    carry = carry / 10;
    result_size++;
}

} void extraLongFactorials(int n) { vector result(1000, 0); result[0] = 1; int result_size = 1;

for (int x = 2; x <= n; x++) {
    multiply(x, result, result_size);
}


for (int i = result_size - 1; i >= 0; i--) {
    cout << result[i];
}
cout << endl;

}