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    def equalizeArray(arr): # Write your code here dic = Counter(arr)

    max_val = max(dic.values())
    
    return (sum(dic.values())-max_val)
    
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    **Simple Python Solution **

    from collections import Counter as c 
    
    def equalizeArray(arr):
        dict = c(arr)
        m = max(dict.values())
        return len(arr)-m 
    
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    Time Complexity:

    def equalizeArray(arr:list):
        lenght = len(arr)
        frequency = {}
        for num in arr:
            if num not in frequency:
                frequency[num] = 1
            else:
                frequency[num] += 1
        
    
        return abs(max(frequency.values()) - lenght)
    
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        Comparator<Long> longComparator = Long::compare;
        Map<Integer, Long> valueMap = arr.stream().collect(Collectors.groupingBy(s -> s, Collectors.counting()));
        List<Long> values = valueMap.values().stream().sorted(longComparator.reversed()).collect(Collectors.toList());
        long mostrepeated = values.get(0);
        long totaloccurences= values.stream().mapToLong(s->s).sum();
        return (int)(totaloccurences - mostrepeated);