int getMoneySpent(vector<int> keyboards, vector<int> drives, int b) {
    int ans = -1;
    for(int k : keyboards){
        for(int d : drives){
            if(k + d > ans && k + d <= b) ans = k + d;
        }
    }
    return ans;
}

def getMoneySpent(keyboards, drives, b):
    
    arr = []
    max = -1
    
    for i in keyboards:
        for j in drives:
            
            sum = i+j
            if sum <= b and sum > max:
                max = sum
                
    return max

fun getMoneySpent(keyboards: Array<Int>, drives: Array<Int>, b: Int): Int {
    var max=0
    for(k in 0 until keyboards.size){
        for(d in 0 until drives.size){
            var sum=keyboards[k]+drives[d]
            if(sum>max && b>=sum){
                max=sum
            }
        }
    }
    return if(max==0) -1 else max
}

sub getMoneySpent {
    my ($keyboard, $drives, $b) = @_;
    
    my $most_expensive = 0;
    my $keyb = 0;
    my $device = 0;
    for (my $i = 0; $i < scalar(@$keyboard); $i++) {
        for (my $j = 0; $j < scalar(@$drives); $j++) {
            if ($keyboard->[$i] < $b || $drives->[$j] < $b) {
                my $sum = $keyboard->[$i] + $drives->[$j];
                if ($sum > $most_expensive && $sum <= $b) {
                    $most_expensive = $sum;
                    $keyb = $keyboard->[$i];
                    $device = $drives->[$j];
                }                
            }            
        }
    }
    return (($keyb + $device) > 0) ? $keyb + $device : -1;
}