We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Algorithms
  3. Implementation
  4. Electronics Shop
  5. Discussions

Electronics Shop

Sort by

recency

|

2395 Discussions

|

  • Rohanandmail
     + 0 comments

    What is the best time complexity that can be achieved?

  • alban_tyrex
     + 0 comments

    Here is my c++ solution, you can find the video here : https://youtu.be/yC-TXToDbD0

    int getMoneySpent(vector<int> keyboards, vector<int> drives, int b) {
    int ans = -1;
    for(int k : keyboards){
        for(int d : drives){
            if(k + d > ans && k + d <= b) ans = k + d;
        }
    }
    return ans;
}

  • rabearimananaha1
     + 0 comments

    Very simple python solution here

    def getMoneySpent(keyboards, drives, b):
    sortedKeyBoards = sorted(keyboards, reverse=True)
    drives = sorted(drives, reverse=True)
    sumMax = 0
    
    for i in range(len(sortedKeyBoards)):
        for j in range(len(drives)):
            sumTemp = sortedKeyBoards[i] + drives[j]
            if ( sumTemp >= sumMax and sumTemp <= b):
                sumMax = sumTemp
                
    return -1 if sumMax == 0 else sumMax

  • arizonacarsales1
     + 0 comments

    I run a car dealership shop in arizona that sells new and used cars. I want to apply this code on my website. I want to sue this code on my magento based website built with magento 2.1 version

  • cromwellkwasi
     + 0 comments

    def getMoneySpent(keyboards, drives, b): # # Write your code here. # sums = [keyboards[i]+ drives[j] if (keyboards[i]+ drives[j]) <= b else -1 for i in range(len(keyboards)) for j in range(len(drives))] return max(sums)