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  1. Prepare
  2. SQL
  3. Aggregation
  4. Top Earners
  5. Discussions

Top Earners

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3483 Discussions

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  • krnsinghshekhaw1
     + 0 comments

    SELECT (months * salary) AS earnings, COUNT(*) AS employee_count FROM employee GROUP BY (months * salary) ORDER BY earnings DESC LIMIT 1;

  • kartikchaurasiy2
     + 0 comments
    SELECT SALARY*MONTHS AS EARNINGS, COUNT(*) FROM EMPLOYEE
GROUP BY EARNINGS
ORDER BY EARNINGS DESC
LIMIT 1

  • hanzalahali1062
     + 0 comments
    select max(salary*months), count(employee_id) from employee where salary*months=(select max(salary*months) from employee);

  • floreaoana22
     + 0 comments

    in MySQL SELECT CONCAT(total_earnings, ' ', employee_count) AS result FROM ( SELECT (Salary * Months) AS total_earnings, COUNT(*) AS employee_count FROM Employee GROUP BY Salary * Months ORDER BY total_earnings DESC LIMIT 1 ) t;

  • leotrinh2810
     + 0 comments
    SELECT
CONCAT(
   MAX(salary*months)
    ,' '
    ,COUNT(name)
      )
FROM Employee
WHERE salary*months =  (SELECT MAX(salary*months) FROM Employee);