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  1. Prepare
  2. Regex
  3. Applications
  4. Detect HTML Tags
  5. Discussions

Detect HTML Tags

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149 Discussions

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  • abhishek_debnath
     + 0 comments

    Python:

    import re; html = "\n".join([input() for _ in range(int(input()))]); print(";".join(sorted(set(re.findall(r"<\s?([a-zA-Z]+[0-9A-Za-z])[^>]>", html)))));

  • torobintu
     + 0 comments

    Perl

    use List::Util qw( uniq );
BEGIN{$, = ";"};

my @allmatch;
while(<>){
    chomp;
    my @matches = m|<([^\s/]+?)[>\s]|g;
    push @allmatch, @matches;
}
my @res = uniq(sort(@allmatch));

print @res;

  • dluksa20
     + 0 comments
    import re
pattern =  r'<(\w+)>?'
lst = []

for i in range(int(input())):
    m = re.findall(pattern, input())
    for i in m:
        if i not in lst:
            lst.append(i)
print(';'.join(sorted(lst)))

  • preethiannjacob
     + 1 comment

    Java 15

    import java.io.*;
import java.util.*;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class Solution {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int n = scanner.nextInt(); scanner.nextLine();
        //one or more spaces before tagname. So \\s*
        Pattern pattern = Pattern.compile("<\\s*(\\w+)[^>]*>");
        TreeSet<String> tags = new TreeSet<String>();
        for(int i=0;i<n;i++)
        {   Matcher matcher = pattern.matcher(scanner.nextLine());
            while(matcher.find())   tags.add(matcher.group(1));
        }
        System.out.println(String.join(";",tags));
    }
}

  • warshout
     + 0 comments

    Javascript solution

    let tags = input.match(/(?<=\<)[^\s>\/]+(?=[\s>])/g)
tags = tags.filter((x, i, a) => a.indexOf(x) == i)
console.log(tags.sort().join(';'))