I know I didnt use defaultdict but I cannot figure out why this code is failing test cases 1,2,3 and 4. Can anyone help me figure out?

n,m = map(int,input().split()) A = list() B = list()

for i in range(n): A.append(input()) for i in range(m): B.append(input())

for i in range (m): count = 0 for j in range(n): if B[i] == A[j]: print(j+1, end = ' ') count += 1 if count == 0: print(-1) print()

from collections import defaultdict

x,y = input().split() B = []

A = defaultdict(list)

for i in range(int(x)): a= input() A[a].append(i+1)

for j in range(int(y)): b= input()

if(b in A.keys()):        
    [print(z,end=" ") for z in A[b]]
else:
    print(-1)

Using Walrus Operator

from collections import defaultdict

n,m = map(int,input().split())

a = defaultdict(list)

for i in range(n): a[input()].append(i+1)

for i in range(m): print(*a[x] if (x:=input()) in a else [-1])

from collections import defaultdict n,m,dd = map(int,input().split()),defaultdict(list)

for i in range(n): dd[input()].append(i+1)

for _ in range(m): print(' '.join(map(str,dd.get(input(),[-1]))))

The statement of this problem is so confusing... spent most of my time figure out where does the m and n come from..

from collections import defaultdict

n, m = map(int, input().split())

d = defaultdict(list)
for i in range(n):
    word = input()
    d[word].append(i + 1)

for j in range(m):
    word = input()
    if len(d[word]) > 0:
        print(' '.join([str(s) for s in d[word]]))
    else:
        print(-1)