from collections import defaultdict

m,n=map(int,input().split())

d=defaultdict(list)

for i in range(m):
    d['A'].append(input())
        
for i in range(n):
    d['B'].append(input())
    
    
for word in d['B']:
    indexes = [i+1 for i,x in enumerate(d['A']) if x == word]
    if indexes:
        print(*indexes)
        
    if word not in d['A']:
        print(-1)

n, m = input().split()

group_A = []
group_B = []

for i in range(int(n)):
    group_A.append(input())
for i in range(int(m)):
    group_B.append(input())
		
for elementB in group_B:   
    
    indices= [str(i+1) for i, elementA in enumerate(group_A) if elementA == elementB]
    if indices:
        print(" ".join(indices))    
    else:
        print("-1")
        

from collections import defaultdict

n, m = map(int, input().split())
word_to_indices = defaultdict(list)

for i in range(n):
    word_to_indices[input()].append(i + 1)

for _ in range(m):
    result = word_to_indices[input()]
    if len(result) == 0:
        print(-1)
        continue

    print(*result)

from collections import defaultdict

if __name__ == '__main__':
    n, m = map(int, input().split())
    words_dict = defaultdict(list)
    for i in range(n):
        words_dict['A'].append(input())
        
    for i in range(m):
        words_dict['B'].append(input())
        
    for word in words_dict['B']:
        indexes = [i+1 for i, x in enumerate(words_dict['A']) if x == word]
        if indexes:
            print(*indexes)
        

# my solution uses enumerate() to create the list of indices to be printed. If a word/letter is not found in group A, minus one is printed instead.
from collections import defaultdict

d = defaultdict(list)
n, m = input().split()
for i in range(int(n)):
    d["A"].append(input())
for j in range(int(m)):
    d["B"].append(input())
    
for letter in d["B"]:
    if letter in d["A"]:
        b_list = [str(i+1) for i, x in enumerate(d["A"]) if x == letter]
        print(" ".join(b_list))
    else:
        print(-1)