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  1. Prepare
  2. Python
  3. Debugging
  4. Default Arguments
  5. Discussions

Default Arguments

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195 Discussions

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  • sefamutlucu
     + 0 comments
    def print_from_stream(n, stream=None):
    if stream is None:
        stream = EvenStream()
    for _ in range(n):
        print(stream.get_next())

  • jjtt0926
     + 1 comment

    Why does the problem say "the task is to debug the existing code" when there is no existing code at all?

    I am extremely cconfused by the problem saying "the task is to debug the existing code". It makes me think I don't need to define OddStream etc. myself. Why not just say define your own OddStream, EvenStream etc. and produce expected output???

  • n_selina
     + 1 comment

    It work perfect after adding stream.init() to reset current variable.

    def print_from_stream(n, stream=EvenStream()):

    stream.__init__()    # add this line to reset self.current
for _ in range(n):
    print(stream.get_next())

  • ayushkrsingh2412
     + 0 comments

    def print_from_stream(n, stream=EvenStream()): stream.init() #initialize the current variable in the EvenStream() for _ in range(n): print(stream.get_next())

  • anubhav_r_garg
     + 0 comments

    This part in the explanation is extremely misleading, Makes you think current should be 2 instead of 0 for even.

    "In the second query, the function print_from_stream(3) is exectuted, which leads to printing values 2,4 and 6 in separated lines as the first three non-negative even numbers."