• + 1 comment

    The runtime complexity is O(N) because M upper bound (2 * 10^5) is lower than N upper bound and even if it was equal (M upper bound = N upper bound), it would be O(N+N), which is O(2N), which could be reduced to O(N).

    • + 0 comments

      I usually analyze runtimes assuming variables are unbounded. I find it to be more useful that way since HackerRank usually creates arbitrary bounds for variables.

      In the bounded case, you are correct, you can consider it to be O(N).

      HackerRank solutions.