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  1. Prepare
  2. Algorithms
  3. Sorting
  4. Counting Sort 1
  5. Discussions

Counting Sort 1

  • emhhacker
     + 0 comments

    My Java solution with o(n) time complexity and o(1) space complexity:

    public static List<Integer> countingSort(List<Integer> arr) {
        // init freq array
        int[] freqArr = new int[100];
        
        //update freq for each val
        for(int element : arr) freqArr[element]++;
        
        //return int array converted into Integer list
        return Arrays.stream(freqArr)
            .boxed()
            .collect(Collectors.toList());
    }