My solutions in Java:

1:

    public static int countingValleys(int steps, String path) {
    
        int seaLevel = 0;
        int valleys = 0;
        boolean isInValley = false;
        for (int i = 0; i < steps; i++) {
            if(path.charAt(i) == 'U'){
                seaLevel++;

            } else {
                seaLevel--;
            }
            
            if(seaLevel < 0) {
                isInValley = true;
            } else if (seaLevel > 0){
                isInValley = false;
            }
            
            if(seaLevel == 0 && isInValley) {
                valleys++;
            }
            
        }
        
        return valleys;
    }

2: more concise

public static int countingValleys(int steps, String path) {

    int seaLevel = 0;
    int valleys = 0;
    for (char step : path.toCharArray()) {
       seaLevel += (step == 'U') ? 1 : -1;

        // Detect if a valley has been exited
       if (seaLevel == 0 && step == 'U') {
         valleys++;
       }
    }

    return valleys;
}

sd

One of the Test Cases is: DUDDDUUDUU

Which clearly has only 1 valley but the expected out is 2. Is this mistake or am I missing something?

can you help to integrate this algorithem script with my Menu prices realted page?I want to use it on my WordPress website.

Here is my c++ solution you can find the video here : https://youtu.be/fgJ-i8RJ1Qw

int countingValleys(int steps, string path) {
    int res = 0, level = 0;
    for(char c : path){
        if(c == 'U'){
            level++;
            if(level == 0) res ++;
        }
        else level--;
    }
    return res;
}

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