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  1. Prepare
  2. Python
  3. Itertools
  4. Compress the String!
  5. Discussions

Compress the String!

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825 Discussions

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  • ericstricker73
     + 0 comments
    from itertools import groupby
groups = []
uniquekeys = []
data = input().strip()
for k, g in groupby(data): 
    groups.append(len(list(g)))      
    uniquekeys.append(int(k))
print(*list(zip(groups,uniquekeys)))

  • paco_dtc
     + 0 comments

    from itertools import groupby

    s = input()

    for k, g in groupby(s): print((list(g).count(k),int(k)), end = " ")

  • wazirzoh1
     + 0 comments

    from itertools import groupby

    s = input().strip() result = []

    for key,group in groupby(s): count = len(list(group)) result.append(f"({count},{key})")

    print(" ".join(result))

  • konf1
     + 0 comments
    from itertools import groupby
print(*[(len(list(g)), int(k)) for k, g in groupby(input())])

  • mirzaayaz_beg191
     + 0 comments
    from itertools import groupby
if __name__ == "__main__":
    data = input()
    result=[]
    for key, group in groupby(data):
        s=[]
        s.append(len(list(group)))
        s.append(int(key))
        print(tuple(s),end=" ")