Python solution:

def compare_lists(llist1, llist2):

current1=llist1
current2=llist2
flag=True
while current1 and current2 and flag is True: 
    if current1.data != current2.data:
        flag=False
    current1=current1.next
    current2=current2.next

if flag is True and current1==current2:
    return 1
else:
    return 0

Here is my c++ solution, you can watch the explanation here : https://youtu.be/sxWBiWg16JU

bool compare_lists(SinglyLinkedListNode* head1, SinglyLinkedListNode* head2) {
    while(head1 != nullptr && head2 !=nullptr) {
        if(head1->data != head2->data) return false;
        head1 = head1 ->next;
        head2 = head2 ->next;
    }
    return head2 == head1;
}

Solution in C

bool compare_lists(SinglyLinkedListNode* head1, SinglyLinkedListNode* head2) {
        SinglyLinkedListNode* curr1 = head1;
        SinglyLinkedListNode* curr2 = head2;

        if (head1 == NULL && head2 == NULL) {return true;}
        if (head1 == NULL || head2 == NULL) {return false;}

        while (curr1 != NULL && curr2 != NULL) {
                if (curr1->data != curr2->data) {
                        return false;
                }

                curr1 = curr1->next;
                curr2 = curr2->next;
        }

return (curr1 == NULL && curr2 == NULL);

}

i need to ask sth using javascript check condition using while(currentnode.next) always gave a runtime error bec the compiler can't read null but when i used just currentnode solved it

simple python solution:

def compare_lists(llist1, llist2):    
    while llist1 and llist2:
        if llist1.data != llist2.data:
            return False
        
        llist1 = llist1.next
        llist2 = llist2.next
        
    if (not llist1 and llist2) or (llist1 and not llist2):
        return False
        
    return True