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  1. Prepare
  2. Data Structures
  3. Linked Lists
  4. Compare two linked lists
  5. Discussions

Compare two linked lists

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995 Discussions

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  • kadirgok00
     + 0 comments
    def compare_lists(llist1, llist2):
    while llist1 or llist2:
        if llist1.data == llist2.data and (llist1_count == llist2_count):
            llist1 = llist1.next
            llist2 = llist2.next
        else:
            return 0
    return 1

  • ashbdash
     + 0 comments
    bool compare_lists(SinglyLinkedListNode* head1, SinglyLinkedListNode* head2) {
    while(head1 && head2 && head1->data == head2->data){
        head1 = head1->next;
        head2 = head2->next;
    }
    if(head1 || head2){
        return false;
    }
    return true;
}

  • alban_tyrex
     + 0 comments

    Here is my c++ solution, you can watch the explanation here : https://youtu.be/sxWBiWg16JU

    bool compare_lists(SinglyLinkedListNode* head1, SinglyLinkedListNode* head2) {
    while(head1 != nullptr && head2 !=nullptr) {
        if(head1->data != head2->data) return false;
        head1 = head1 ->next;
        head2 = head2 ->next;
    }
    return head2 == head1;
}

  • reverse_
     + 0 comments

    Solution in C 

    bool compare_lists(SinglyLinkedListNode* head1, SinglyLinkedListNode* head2) {
    SinglyLinkedListNode* local_head1 = head1;
    SinglyLinkedListNode* local_head2 = head2;
    while(local_head1 != NULL && local_head2 != NULL)
    {
            if(local_head1->data == local_head2->data)
            {
                    local_head1 = local_head1->next;
                    local_head2 = local_head2->next;

            }
            else {
                return 0;
            }
        if(local_head1 != NULL && local_head2 != NULL){
        }
        else
        {
            if(local_head1 == NULL && local_head2 == NULL) return 1;
            else return 0;
        }
      
    }
    return 1;
    }

  • abhisheksumesh21
     + 1 comment

    I don't get whats wrong, the first test case always fails.

    bool compare_lists(SinglyLinkedListNode* head1, SinglyLinkedListNode* head2) {

    while(head1->next!=NULL && head2->next!=NULL)
    {
        if(head1->data!=head2->data)
        {
            return 0;
            break;
        }
            
        head1=head1->next;
        head2=head2->next;
    }
    return 1;
}