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  1. Prepare
  2. Algorithms
  3. Warmup
  4. Compare the Triplets
  5. Discussions

Compare the Triplets

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4268 Discussions

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  • Discordharp
     + 0 comments

    Python 3 solution:

        scores = [0, 0]
    for count, triplet in enumerate(a):
        scores[0] += a[count] > b[count]
        scores[1] += b[count] > a[count]
    return scores

  • 2k23_csai2313671
     + 0 comments

    IN C++;

    vector compareTriplets(vector a, vector b) { int alice=0; int bob=0;

    for(int i=0;i<3;i++)    
{
    if(a[i]>b[i])
    {
        ++alice;
    }
    else if(a[i]<b[i]){
        ++bob;
    }
}
return {alice,bob};

    }

  • ggui50381
     + 1 comment

    c# int aliceScore = 0; int bobScore = 0; for(int i =0;i<3;i++){ if(a[i] > b[i]){ aliceScore++; } else if(a[i] {aliceScore,bobScore};

  • manipoint
     + 0 comments

    teamA = 0 teamB = 0

    for i in range(len(a)):
    if a[i] > b[i]:
        teamA +=1
    elif a[i]<b[i]:
        teamB +=1
return list([teamA,teamB])

  • ivan_romero_dev1
     + 0 comments
    public static List<Integer> compareTriplets(List<Integer> a, List<Integer> b) {
        var alices = 0;
        var bobs = 0;
        for (int i = 0; i < 3; i++) {
            if(a.get(i) > b.get(i))
                alices++;
            else if(a.get(i) < b.get(i))
                bobs++;
        }
        return List.of(alices, bobs);
    }