This was so beneficial for me as you have very well explained the procedure to draw the polygon K laser clinic Aylesbury and everything was well explained. It is a good site follow as everything is well explained which made it easy for everyone to understand the topic

As usual, I think the editorial code/approach is needlessly compex. There's no need for any fancy data structures like segment tree or Fenwick tree, just a few standard arrays:

WARNING: Low-key spoilers ahead. No implementation code, just declarations.

int A[200010]; // Input array

int next_index[200010]; // next_index[i] is the next index j such that A[i] = A[j], or -1 if no such index exists
int prev_index[200010]; // prev_index[i] is the previous index j such that A[i] = A[j], or -1 if no such index exists

bool start_index[200010]; 

// start_index[i] = true if DP algorithm should be run on a segment beginning at index i

long long DP[200010][2] = {0}; 

// DP[i][0] = count of binary subsets ending with a zero bit at index i
// DP[i][1] = count of binary subsets ending with a one bit at index i

long long sums[200010][2] = {0};

// Prefix sum array of values in DP

Anyway, I still found this to be a very interesting and fun challenge. Sadly, I'm starting to run out of DP-related problems to solve on this site... :/

Laparoscopic ovarian drilling is a surgical treatment that can trigger ovulation in women who have laparoscopic surgery for endometriosis polycystic ovary syndrome (PCOS). Electrocautery or a laser is used to destroy parts of the ovaries. This surgery is not commonly used.

I am not sure if the output and input shared here could provide any idea regarding the problem. I saw the functions shared here however for the same value of “4” there are 2 different outcomes. How is it possible. Please make a detailed description explaining the criteria. infertility hospitals in kerala

Terrible example test cases. No explanation how and why the answer was derived.