SHORTEST CODE TO THIS QUESTION

int min(int a, int b) {int c=a; if(a>b) c=b; return c; }

int main() { int t,n,a,b,c,d,i,j,k,l; scanf("%d",&t);

while(t--)
{int x=0;
    scanf("%d %d %d %d %d",&n,&a,&b,&c,&d);

    for(i=min(d,n/10);i>=0;i--)
    {
        for(j=min((n-10*i)/5,c);j>=0;j--)
        {
            for(k=min(b,(n-10*i-5*j)/2);k>=0;k--)
            {
                for(l=min(a,(n-10*i-5*j-2*k));l>=0;l--)
                {
                    if(10*i+5*j+2*k+l==n)
                    {
                        x++;
                        break;
                    }
                }
            }
        }
    }
    printf("%d\n",x);
}
return 0;

}