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def getWays(n, c): count = [0]*(n+1) count[0] = 1 c.sort(reverse = True) for coin in c: for i in range(coin, n +1): count[i] += count[i-coin] return count[n]
sorting is done in order to understand how denomination is formed
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The Coin Change Problem
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sorting is done in order to understand how denomination is formed