void update(int *a,int *b) { int sum= (*a)+(*b); int diff= abs((*a)-(*b));
(*a)=sum; (*b)=diff; } this may help :)

Hey, this is my code. Insights would be appreciated. Happy learning!

#include <stdio.h>
#include <math.h>

void update(int *a,int *b) {
    // Complete this function 
    int temp;``
    temp = *a;  
    (*a) = (*a) + (*b);
    (*b) = abs((temp)-(*b));
}

Using Ternary Operator

void update(int *a,int *b) {
    int x=*a + *b;
    int diff=*a-*b;
    int y=(diff<0 ? -diff : diff;
    *a=x;
    *b=y;
}

`Hey guys :

include

void update(int *a,int *b) { // Complete this function
int sum = *a + *b; int sub = abs(*a - *b);

*a = sum;````
*b = sub;

} `

Simplest solution is below,

include

using namespace std;

void update(int *pa,int *pb){ int temp = *pa; *pa = *pa + *pb; *pb = temp > *pb ? temp - *pb : *pb-temp; }

int main(){ int a,b; cout <<"Enter a & b: "; cin >>a>>b; update(&a,&b); cout <<"sum: "<