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  1. Prepare
  2. C++
  3. Introduction
  4. For Loop
  5. Discussions

For Loop

  • AnonMousy1
     + 0 comments

    Hello there! My code isnt the most optimal, but i used my knowledge of switch case and solved this:

    int main(){
	int a, b;
	cin >> a >> b ;
	for(int i=a; i<=b; i++){
		if(i <= 9 && i >= 1){
				switch(i){
				case 1:
					cout << "one" << endl;
					break;
				case 2:
					cout << "two" << endl;
					break;
				case 3:
					cout << "three" << endl;
					break;
				case 4:
					cout << "four" << endl;
					break;
				case 5:
					cout << "five" << endl;
					break;
				case 6:
					cout << "six" << endl;
					break;
				case 7:
					cout << "seven" << endl;
					break;
				case 8:
					cout << "eight" << endl;
					break;
				case 9:
					cout << "nine" << endl;
					break;
				default:
					break;
				}
		}else{
			if(i%2==0){
				cout << "even" << endl;
			}else{
				cout << "odd" << endl;
			}
		}
	}
	return 0;
}