We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Mathematics
  3. Combinatorics
  4. Building a List
  5. Discussions

Building a List

Sort by

recency

|

47 Discussions

|

  • adrien_cordonni1
     + 0 comments

    Python oneliners:

    from itertools import combinations
def solve(s):
    return sorted(''.join(x) for r in range(1,1+len(s)) for x in combinations(s,r))

    Or for the fun to use accumulate instead of range(len()):

    from itertools import combinations, accumulate
def solve(s):
    return sorted(''.join(x) for r in accumulate(s) for x in combinations(s,len(r)))

  • dostiyari0786
     + 0 comments

    Can it will be helpful Trusted Commercial Glass Repair Professionals for my business?

  • eiduladh_a_wish1
     + 0 comments

    And what does it mean to be a contractor? Well, contracting is one of the most popular forms of self-employment. In the absence of an official Concetti Contracting definition, a contractor is widely regarded as a one-person business who provides services to clients via their own limited company on a temporary basis.

  • macdonald_l_kyn
     + 0 comments

    Python Solution, I'm using a recursive method here 

    def generateSubsets(s):
    if not s:
        return ['']
    subsets = generateSubsets(s[1:])
    return subsets + [s[0] + subset for subset in subsets]


def solve(s):
    pl = generateSubsets(s)
    pl.sort()
    pl.pop(0)
    return pl

  • murshid_islam
     + 0 comments

    My Python code that passed all the test cases:

    from itertools import combinations
def solve(s):
    n = len(s)
    combs = []
    for i in range (1, n+1):
        # find all combinations of size 'i' from 's'
        temp = combinations(s, i)    
        # add those combinations to the list 'combs'
        combs += [''.join(e) for e in temp]
    combs.sort()
    return combs