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  • + 0 comments
    def bonAppetit(bill, k, b):
        # Write your code here
        
        total = 0
        for i in bill : 
            total += i
        actual = (total - bill[k]) // 2
        ca = b - actual
         
        if ca == 0:
            print("Bon Appetit")
        else: 
            print(ca)
    
  • + 0 comments

    import java.io.; import java.math.; import java.security.; import java.text.; import java.util.; import java.util.concurrent.; import java.util.function.; import java.util.regex.; import java.util.stream.*; import static java.util.stream.Collectors.joining; import static java.util.stream.Collectors.toList;

    class Result {

    /*
     * Complete the 'bonAppetit' function below.
     *
     * The function accepts following parameters:
     *  1. INTEGER_ARRAY bill
     *  2. INTEGER k
     *  3. INTEGER b
     */
    
    public static void bonAppetit(List<Integer> bill, int k, int b) {
    // Write your code here
    int actual=0;
    
    for(int i=0;i<bill.size();i++){
        if(i==k){
            continue;
        }
        actual+=bill.get(i);
    
    }
    actual=actual/2;
    if(actual==b){
        System.out.println("Bon Appetit");
    }
    else{
        System.out.println(b-actual);
    }
    
    }
    

    }

    public class Solution { public static void main(String[] args) throws IOException { BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));

        String[] firstMultipleInput = bufferedReader.readLine().replaceAll("\\s+$", "").split(" ");
    
        int n = Integer.parseInt(firstMultipleInput[0]);
    
        int k = Integer.parseInt(firstMultipleInput[1]);
    
        List<Integer> bill = Stream.of(bufferedReader.readLine().replaceAll("\\s+$", "").split(" "))
            .map(Integer::parseInt)
            .collect(toList());
    
        int b = Integer.parseInt(bufferedReader.readLine().trim());
    
        Result.bonAppetit(bill, k, b);
    
        bufferedReader.close();
    }
    

    }

  • + 0 comments

    Here is my c++ solution you can find the video here : https://youtu.be/MHFroRIBGQc

    void bonAppetit(vector<int> bill, int k, int b) {
        int s = accumulate(bill.begin(), bill.end(), -1 * bill[k]);
        int c = s / 2;
        if(c == b) cout << "Bon Appetit";
        else cout << b - c;
    }
    
  • + 0 comments

    Splitting a bill should always be fair! If someone skips an item, they shouldn’t have to pay for it. This LeetCode problem is a great way to practice handling expenses with coding—similar to tracking scores in [racing games](hilclimbracing.com). Try solving it and see if you get Bon Appetit or a refund!

  • + 0 comments

    My c# submission;

    public static void bonAppetit(List<int> bill, int k, int b)
        {
            var annaPayment = (bill.Sum() - bill[k])/2;
    
            Console.WriteLine(annaPayment == b ? "Bon Appetit" : (b - annaPayment).ToString());
        }