Here is my c++ solution you can find the video here : https://youtu.be/MHFroRIBGQc

void bonAppetit(vector<int> bill, int k, int b) {
    int s = accumulate(bill.begin(), bill.end(), -1 * bill[k]);
    int c = s / 2;
    if(c == b) cout << "Bon Appetit";
    else cout << b - c;
}

Splitting bills can be tricky, like when you're with friends at a restaurant. It's like if Top Roofing Contractors in Hartsville charged everyone equally for a job, even if some didn't need the full service.

Here is my c++ solution you can find the video here https://bitlifeapk.org

Java 8

    bill.remove(k);
    int actual = bill.stream().mapToInt(Integer::intValue).sum() / 2;
    if(actual == b){
        System.out.println("Bon Appetit");
    } else {
        int refund = b - actual;
        System.out.println(refund);
    }

C# * public static void bonAppetit(List bill, int NoEat, int charged) * { * //remove item that she doesn't it from bill list * bill.RemoveAt(NoEat); * //sum the bill and minus the amount charged * int refund = (charged - (bill.Sum()/2)); * //do simple if else then in console.write IF balance is 0, write Bon Appetit else write refund * Console.Write(refund == 0 ? "Bon Appetit": refund); * }