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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Between Two Sets
  5. Discussions

Between Two Sets

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  • christianivanca1
     + 0 comments

    the resolute in php function getTotalX(b) { a; sort(sb = sb); sb); i=1;mb;count); } function isperfect (a){ foreach(i => Extra close brace or missing open bracej,Extra open brace or missing close braceb as val){ if(j != 0 ){ return false; } } return true; }

  • mrityunjay6492
     + 0 comments

    Code in C#

    int count = 0; List factorsOfAarray = new(); int minimumb = b.Min(); for (int i = a.Max(); i <= minimumb; i++) { bool remainderOperator = true; foreach (var element in b) { if (element % i != 0) { remainderOperator = false; } } if (remainderOperator) { bool factorsOfinteger = true; foreach (var elementina in a) { if (i % elementina != 0) { factorsOfinteger = false; } } if (factorsOfinteger) { count += 1; } } }

    Console.WriteLine(count)

  • raskolny
     + 0 comments

    My JavaScript code is right and passes all tests, however its submission fails with error:

    We couldn't process your submission. Please subit your code again!

    I have tried to reset the code and copy back my portion of code, in vain. Submission always fails.

    HackerRank admins, please check and fix.

    Thanks.

  • nicokurtz01
     + 0 comments
    int getTotalX(vector<int> a, vector<int> b) {
    // assume vectors are sorted and a_n <= b_1    
    int betweenCount = 0;
    
    for (int q = a.back(); q <= b.front(); q += a.back()) {
        bool isMultiple = std::all_of(a.begin(), a.end(),
            [q] (int el) { return q % el == 0; }); 
        bool isFactor = std::all_of(b.begin(), b.end(),
            [q] (int el) { return el % q == 0; });
        if (isMultiple && isFactor)
            betweenCount++;
    }
    
    return betweenCount;
}

  • ijamesrmartin
     + 0 comments

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