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For Python3 Platform

def sum_of_digits(n):
    sum = 0
    
    while(n > 0):
        sum = sum + n % 10
        
        n = n//10
    
    return sum

n = int(input())
num_digit_sum = sum_of_digits(n)
result = n

for div in range(1, n//2+1):
    if(n % div == 0):
        if(sum_of_digits(div) > num_digit_sum):
            num_digit_sum = sum_of_digits(div)
            result = div
        elif(sum_of_digits(div) == num_digit_sum):
            result = min(result, div)

print(result)