function beautifulPairs(A: number[], B: number[]): number {
    let counter: number = 0;
    
    /*
    * Looping through the A array and finding if there are any matched in the,
    * if there are then we count up and remove the element from the B array to
    * prevent duplicates being counted again
    */
    A.forEach((num) => {
        if (B.includes(num)) {
            counter ++;
            const indexToRemove: number = B.indexOf(num);
            B.splice(indexToRemove, 1)
        }
    })
    
    return counter === A.length ? counter -1 : counter +1;

}