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->The code starts with a counter (count) set to 0 to keep track of matches.
2->Single Item Check:
->If A has only one item, it immediately returns 0, meaning it skips the rest of the process since there’s only one item to compare.
3->Count Matches:
->For each item in A, the code checks if it also exists in B.
->If a match is found, it adds 1 to count and removes that item from B so it doesn’t get counted again.
4->Adjust the Final Count:
->After counting, the code checks :
=>If count is less than the length of A, meaning not every item in A had a match, it returns count + 1 (adding a little "bonus").
=>If all items in A matched items in B (count == len(A)), it returns len(A) - 1 (reducing the count by one).
If count is less than the length of A, meaning not every item in A had a match, it returns count + 1 (adding a little "bonus").
If all items in A matched items in B (count == len(A)), it returns len(A) - 1 (reducing the count by one).
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Beautiful Pairs
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This worked, but could you also explain how does this logic work ?
1->Initialize a Counter:
->The code starts with a counter (count) set to 0 to keep track of matches.
2->Single Item Check:
->If A has only one item, it immediately returns 0, meaning it skips the rest of the process since there’s only one item to compare.
3->Count Matches:
->For each item in A, the code checks if it also exists in B. ->If a match is found, it adds 1 to count and removes that item from B so it doesn’t get counted again.
4->Adjust the Final Count:
->After counting, the code checks :
=>If count is less than the length of A, meaning not every item in A had a match, it returns count + 1 (adding a little "bonus"). =>If all items in A matched items in B (count == len(A)), it returns len(A) - 1 (reducing the count by one). If count is less than the length of A, meaning not every item in A had a match, it returns count + 1 (adding a little "bonus"). If all items in A matched items in B (count == len(A)), it returns len(A) - 1 (reducing the count by one).