My python3 solution

def beautifulDays(i, j, k): # Write your code here

b = 0
for x in (range(i,j+1)):
    r = int(str(x)[::-1])

    if (abs(x-r)%k == 0):
        b +=1
return(b)

def beautifulDays(i, j, k): count=0 for day in range(i,j+1): d1=str(day) d2=d1[::-1] dif=abs(int(d1)-int(d2))%k==0 if dif: count += 1 return count # Write your

Much more optimal solution in java : `

import java.util.Scanner;

public class BeautifulDaysAtTheMovies {

public static int beautifulDays(int i, int j, int k) {
    int count = 0;

    for (int day = i; day <= j; day++) {
        int reversed = reverseNumber(day);
        if (Math.abs(day - reversed) % k == 0) {
            count++;
        }
    }

    return count;
}

private static int reverseNumber(int num) {
    int reversed = 0;
    while (num > 0) {
        reversed = reversed * 10 + num % 10;
        num /= 10;
    }
    return reversed;
}

public static void main(String[] args) {
    Scanner scanner = new Scanner(System.in);

    // Read input values
    int i = scanner.nextInt();
    int j = scanner.nextInt();
    int k = scanner.nextInt();

    // Compute and print the number of beautiful days
    System.out.println(beautifulDays(i, j, k));

    scanner.close();
}

} `

Here my java solution

public static int beautifulDays(int i, int j, int k) { int count = 0;

for (int m = i; m <= j; m++) {
    int n = m;
    int reversed = 0;

    while (n != 0) {
        reversed = reversed * 10 + n % 10;
        n /= 10;
    }

    if (Math.abs(m - reversed) % k == 0) {
        count++;
    }
}

return count;

}

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