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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Beautiful Days at the Movies
  5. Discussions

Beautiful Days at the Movies

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1776 Discussions

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  • zkop354
     + 0 comments
    func reverse(number int32) int32 {
    if number < 10 {
        return number
    }
    
    reverse := int32(0)
    
    for number > 0 {
        
        r := number % 10 
        reverse = reverse * 10 + r
        
        number = number / 10
    }
    return reverse
 }

func beautifulDays(i int32, j int32, k int32) int32 {
    // Write your code here
    count := int32(0)
    
    for i:= i; i <= j; i++ {
        if (i - reverse(i)) % k == 0{
            count++
        }
    }
    return count   
}

  • zkop354
     + 0 comments

    `

    func reverse(number int32) int32 { if number < 10 { return number }

    reverse := int32(0)

for number > 0 {

    r := number % 10 
    reverse = reverse * 10 + r

    number = number / 10
}
return reverse

    } `

  • nice00guy69
     + 0 comments

    Step 1: Solve it like a noob Step 2: Be the 'Ok guy'

        # count = 0
    # for day in range(i, j+1):
    #     if (day-int(str(day)[::-1])) % k == 0:
    #         count += 1
    # return count
    
    return sum((day-int(str(day)[::-1])) % k == 0 for day in range(i, j+1))

  • sheiktaher1995
     + 0 comments

    //check the code int reverse_num(int num){ int temp = 0; int neg = num < 0; if (neg) num = -num; while(num){ temp = (temp*10) + (num%10); num /= 10;
    } return neg ? -temp:temp; }

    int beautifulDays(int i, int j, int k) { int beautiful_count = 0;

    for(int day=i; day <= j; day++){
    if(abs(day - reverse_num(day)) % k == 0) {
        beautiful_count++;
    }
}
return beautiful_count;

    }

  • henrylong7191
     + 0 comments
    function reverseNumber(num: number) {
  let rev = 0;

  while (num > 0) {
    rev = rev * 10 + (num % 10);
    num = Math.floor(num / 10);
  }

  return rev;
}

function beautifulDays(i: number, j: number, k: number): number {
  let cnt = 0;

  for (let num = i; num <= j; num++) {
    let reversed_num = reverseNumber(num);
    if ((num - reversed_num) % k === 0) {
      cnt++;
    }
  }

  return cnt;
}