def beautifulDays(i, j, k): count=0 for day in range(i,j+1): d1=str(day) d2=d1[::-1] dif=abs(int(d1)-int(d2))%k==0 if dif: count += 1 return count # Write your

Much more optimal solution in java : `

import java.util.Scanner;

public class BeautifulDaysAtTheMovies {

public static int beautifulDays(int i, int j, int k) {
    int count = 0;

    for (int day = i; day <= j; day++) {
        int reversed = reverseNumber(day);
        if (Math.abs(day - reversed) % k == 0) {
            count++;
        }
    }

    return count;
}

private static int reverseNumber(int num) {
    int reversed = 0;
    while (num > 0) {
        reversed = reversed * 10 + num % 10;
        num /= 10;
    }
    return reversed;
}

public static void main(String[] args) {
    Scanner scanner = new Scanner(System.in);

    // Read input values
    int i = scanner.nextInt();
    int j = scanner.nextInt();
    int k = scanner.nextInt();

    // Compute and print the number of beautiful days
    System.out.println(beautifulDays(i, j, k));

    scanner.close();
}

} `

Here my java solution

public static int beautifulDays(int i, int j, int k) { int count = 0;

for (int m = i; m <= j; m++) {
    int n = m;
    int reversed = 0;

    while (n != 0) {
        reversed = reversed * 10 + n % 10;
        n /= 10;
    }

    if (Math.abs(m - reversed) % k == 0) {
        count++;
    }
}

return count;

}

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Cinegato sounds like an exciting platform for movies and films! If it helps filmmakers, producers, or movie enthusiasts discover, create, or stream content, it could be a game-changer in the industry. Whether cinegato offers reviews, recommendations, or filmmaking tools, it is always great to have innovative solutions in the entertainment space. Would love to know more about how it works and what makes it stand out from other platforms.