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One possible way to solve this is calculate all probabilities to get an interview:
P(A)~P(B)~P(C) + ~P(A)P(B)~P(C) + ~P(A)*~P(B)*P(C) + P(A)P(B)~P(C)+ ...
= Ans
But:
Ans + ~P(A)~P(B)~P(C) = 1
So, you just need to find 1 - ~P(A)~P(B)~P(C)
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Basic Probability Puzzles #9
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One possible way to solve this is calculate all probabilities to get an interview: P(A)~P(B)~P(C) + ~P(A)P(B)~P(C) + ~P(A)*~P(B)*P(C) + P(A)P(B)~P(C)+ ... = Ans
But: Ans + ~P(A)~P(B)~P(C) = 1 So, you just need to find 1 - ~P(A)~P(B)~P(C)