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it says there are 2 vacancies meaning the probabilities of them getting selected are mutually exclusive. so the answer is P(A!B)+P(!AB)=P(A)*P(!B)+ P(!A)*P(B)=(1/3*4/5)+(2/3*1/5)=2/5
P(!A) is the probability that A is not selected.
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Basic Probability Puzzles #10
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it says there are 2 vacancies meaning the probabilities of them getting selected are mutually exclusive. so the answer is P(A!B)+P(!AB)=P(A)*P(!B)+ P(!A)*P(B)=(1/3*4/5)+(2/3*1/5)=2/5 P(!A) is the probability that A is not selected.