This one line worked very well

sed -e '/a/d' -e '/A/d'

This one line worked very well

sed -e '/a/d' -e '/A/d'

a=($(cat))

p=(${a[@]/* a */})

echo ${p[@]}

i set the input as array a

then i edited array a into a new array p, removing all instances of "a", as well as the characters before and after "a". (remove the spaces in * a *)

then i used echo to show me the new array p

does this one make sense

This was my solution> #!/bin/bash

i=10 i2=0 array1=()

while ((i));do read dato array1=("dato") #echo "((i2+1)) done

declare -a patter=(${array1[@]/[a-zA-Z]a/})

echo ${patter[@]}

grep -vi a | awk '{
    if( $0 )
    print $0
    else
    print " "
}'

Mostly simple, but not the correct way